php镜像站怎么写de

以下是一个简单的 PHP 镜像站示例代码：

<?php
// 获取参数
$url = isset($_GET["url"]) ? $_GET["url"] : "";
if (!$url) {
    echo "请输入要获取的 URL";
    exit;
}

// 获取远程文件内容
$content = file_get_contents($url);
if (!$content) {
    echo "获取内容失败";
    exit;
}

// 输出内容
header("Content-Type: " . get_mime_type($url));
echo $content;

// 获取 MIME 类型
function get_mime_type($url) {
    $mime_types = array(
        "txt" => "text/plain",
        "html" => "text/html",
        "php" => "text/html",
        "css" => "text/css",
        "js" => "application/javascript",
        "json" => "application/json",
        "xml" => "application/xml",
        "swf" => "application/x-shockwave-flash",
        "flv" => "video/x-flv",
        "png" => "image/png",
        "jpe" => "image/jpeg",
        "jpeg" => "image/jpeg",
        "jpg" => "image/jpeg",
        "gif" => "image/gif",
        "bmp" => "image/bmp",
        "ico" => "image/vnd.microsoft.icon",
        "tiff" => "image/tiff",
        "tif" => "image/tiff",
        "svg" => "image/svg+xml",
        "svgz" => "image/svg+xml"
    );
    $ext = pathinfo($url, PATHINFO_EXTENSION);
    return isset($mime_types[$ext]) ? $mime_types[$ext] : "application/octet-stream";
}
?>

此示例代码可以通过 GET 请求获取指定 URL 的内容，并输出该内容的 MIME 类型。您可以将此代码上传至您的 PHP 主机或服务器，并访问该文件来获取远程文件的内容。