JAVA删除字符串固定下标字串的实现

JAVA删除下标字串 JAVA删除固定下标字串 2023-05-15 09:05:48 537人浏览安东尼

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摘要

目录需要修改的报文实现代码如下多存在多个不符合规定的数据然后你要删掉怎么操作呢？实现代码如下此解决方式在企业中有所应用，适合Java初级开发学习，参考。需要修改的报文当你拿到的报

需要修改的报文

当你拿到的报文是这样的

{
    "input": {
        "sdfsn": "23u4209350-2",
        "fsfs": "128412094",
        "sgsgsg": "15821059",
        "inssgsuplc_admdfdfdvs": "125125332",
        "dgh": "125215312",
        "dfgdfg": "215215",
        "sdhdsh": "",
        "sdfsn": "",
        "shdfshdshdsh": "shsdh",
        "sdhdsh": "shsh.0",
        "shsdhsd": "1",
        "shsdh": "1607",
        "input": {
            "data": {
                "dhfsdhsd": "235325",
                "shsdhsdh": "03",
                "dgd": "BE0445360",
                "dfhfdh": "11",
                "dshshsd": 76.56,
                "ghjrfgj": "01",
                "grjf": "234623626",
                "hjfd": "236436",
                "djfdfgjdfj": "45634",
                "exp_Content": "{"gdsg":"01","gjfj":"658568","fjfj":"5675467","ghfjfgkj":"68568","vmgfvj":"658568","gfhjgfyk":"0","fghkfghkg":"5474567"}",
                "dfjgdfj": "",
                "dfjdfjgdfj": "56745745",
                "dfgjdfgjh": 45756758,
                "jdfgjhfdgj": 0,
            }
        }
    },
    "output": {
        "output": {
            "r757": {
                "dhfsdhsd": "235325",
                "shsdhsdh": "03",
                "dgd": "BE0445360",
                "dfhfdh": "11",
                "dshshsd": 76.56,
                "ghjrfgj": "01",
                "grjf": "234623626",
                "hjfd": "236436",
                "djfdfgjdfj": "45634",
                "exp_content": "",
                "dfjgdfj": "",
                "dfjdfjgdfj": "56745745",
                "dfgjdfgjh": 45756758,
                "jdfgjhfdgj": 0,
            },
            "sdfgsdfg": [
                {
                    "sgasgag": "4673476",
                    "agasgdas": 5675467,
                    "asgasgasg": "",
                    "asdgasgas": 4567456754,
                    "dhsdsxchsdh": 54675467,
                    "sdfhsdhsdh": "5674756457"
                }
            ]
        },
        "erherth": 0,
    }
}

这一看就知道上边的报文在postman里边肯定会报错，因为exp_Content，因此他又没有用到，所以你想把他删掉。其实也没那么难删

也就是用到了流转字符串。字符串固定字符查找，然后进行字符串转字符流，删掉字符流中固定字符，之后再转回来。因为字符串已经是final了所以很多用法都是使用字符串转字符流实现的

实现代码如下

    private JSONObject resolveApplicationjson(httpservletRequest request) {
        InputStream is = null;
        String json = null;
        try {
            is = request.getInputStream();
            json = IOUtils.toString(is, "UTF-8");
            json=json.replaceAll("\\r|\n|\t","");
            int index=  json.indexOf("exp_Content");
            int indexfirst=json.indexOf("{", index);
            int indexlast=json.indexOf("}",index);
            if (index!=-1 && indexlast !=-1 &&indexfirst !=-1) {
            	  StringBuffer stringBuffer = new StringBuffer(json);
                  stringBuffer.delete(indexfirst,indexlast+1);
                  json=stringBuffer.toString();
			}
          
     
        } catch (IOException e) {
            throw new RuntimeException("CANNOT get reader from request!", e);	
        } finally {
            if (is != null) {
                try {
                    is.close();
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
        }

        try {
            return new JSONObject(json);
        } catch (JSONException e) {
            throw new RuntimeException("CANOT CONVET JSON:[" + json + "] to JSONObject!", e);
        }
    }

多存在多个不符合规定的数据然后你要删掉怎么操作呢？

这也很简单，如果你看了这一篇文章，你要更好的解决方式，期待一起探讨，学习进步(＾－＾)V

当你拿到的报文是这样的。

{
    "input": {
        "sdfsn": "23u4209350-2",
        "fsfs": "128412094",
        "sgsgsg": "15821059",
        "inssgsuplc_admdfdfdvs": "125125332",
        "dgh": "125215312",
        "dfgdfg": "215215",
        "sdhdsh": "",
        "sdfsn": "",
        "shdfshdshdsh": "shsdh",
        "sdhdsh": "shsh.0",
        "shsdhsd": "1",
        "shsdh": "1607",
        "input": {
            "data": {
                "dhfsdhsd": "235325",
                "shsdhsdh": "03",
                "dgd": "BE0445360",
                "dfhfdh": "11",
                "dshshsd": 76.56,
                "ghjrfgj": "01",
                "grjf": "234623626",
                "hjfd": "236436",
                "djfdfgjdfj": "45634",
                "exp_Content": "{"gdsg":"01","gjfj":"658568","fjfj":"5675467","ghfjfgkj":"68568","vmgfvj":"658568","gfhjgfyk":"0","fghkfghkg":"5474567"}",
                "dfjgdfj": "",
                "dfjdfjgdfj": "56745745",
                "dfgjdfgjh": 45756758,
                "jdfgjhfdgj": 0,
            }
        }
    },
    "output": {
        "output": {
            "r757": {
                "dhfsdhsd": "235325",
                "shsdhsdh": "03",
                "dgd": "BE0445360",
                "exp_Content": "{"gdsg":"01","gjfj":"658568","fjfj":"5675467","ghfjfgkj":"68568","vmgfvj":"658568","gfhjgfyk":"0","fghkfghkg":"5474567"}",
                "dfhfdh": "11",
                "dshshsd": 76.56,
                "ghjrfgj": "01",
                "grjf": "234623626",
                "hjfd": "236436",
                "djfdfgjdfj": "45634",
                "exp_content": "{"gdsg":"01","gjfj":"658568","fjfj":"5675467","ghfjfgkj":"68568","vmgfvj":"658568","gfhjgfyk":"0","fghkfghkg":"5474567"}",
                "dfjgdfj": "",
                "dfjdfjgdfj": "56745745",
                "dfgjdfgjh": 45756758,
                "jdfgjhfdgj": 0,
            },
            "sdfgsdfg": [
                {
                    "sgasgag": "4673476",
                    "agasgdas": 5675467,
                    "asgasgasg": "",
                    "asdgasgas": 4567456754,
                    "dhsdsxchsdh": 54675467,
                    "sdfhsdhsdh": "5674756457"
                }
            ]
        },
        "erherth": 0,
    }
}

解决方式如下：根据需要写出正则表达式，再使用正则看看有几个这样的不需要的符号，然后循环遍历几次，之后找到这部分，最后删除掉。

实现代码如下

# 全局变量
private static String REGEX = "exp_[c,C]ontent";

# 方式方法
Pattern p = Pattern.compile(REGEX);
        // 获取 matcher 对象
        Matcher m = p.matcher(JSON);
        List<Integer> list = new ArrayList();
        while(m.find()){
            list.add(m.start());
        }
        int index=0;
        int indexfirst=0;
        int indexlast=0;
        for (int j = 0; j < list.size(); j++) {
             index=JSON.indexOf("exp_",indexlast);
             indexfirst=JSON.indexOf("{", index);
             indexlast=JSON.indexOf("}",index);
            StringBuffer stringBuffer =null;
            if (indexlast !=-1 &&indexfirst !=-1) {
                stringBuffer = new StringBuffer(JSON);
                stringBuffer.delete(indexfirst,indexlast+1);
            }
            JSON=stringBuffer.toString();
        }

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