C++实现将长整型数转换为字符串的示例代码

#include <iOStream>
 
using namespace std;
 
char *convertLongToStr(long L) {
    int i = 1;
    int n = 1;
    while (!(L / i < 10)) {
        i *= 10;
        ++n;
    }
 
    char *str = (char *) malloc(n * sizeof(char));
    int j = 0;
    while (L) {
        str[j++] = (char) ((int) (L / i) + (int) '0');
        L = L % i;
        i /= 10;
    }
 
    // A significant line to denote the end of string.
    str[n] = '\0';
 
    return str;
}
 
int main() {
    long l = 123456789;
    char *str = convertLongToStr(l);
    cout << str << endl;
}
 
// Output:

//转化函数
string transfer_Num(int num){
 char temp=num%10+48;
 string m_temp="";
 if(num>=10)
  m_temp+=transfer_Num(num/10);
 m_temp+=temp;
 return m_temp;
} 

int main(){
 int a=4876867;
 string temp=transfer_Num(a);
 cout<<temp;
 return 0;
}