PHP字符串中提取文件名的实例方法

<?php
$path = 'www.example.com/public_html/index.php';
$file = basename($path, ".php");
echo $file."\n";

<?php
$path = 'www.example.com/public_html/index.php';
$file_name = substr(strrchr($path, "/"), 1);
echo $file_name."\n"; // "index.php"

<?php
//获取连接里边的id
$url ='Http://www.rong123.com/cjbkscbsd/x_dfsdfs/24454_1_1.html';
function getIdByUrl($url) {
    $id ='';
    $filename =basename($url,".html");
    $id =str_replace('-','_',$filename);
    if(strstr($id,'_')) {
        $conids =explode('_',$id);
        $id =$conids[0];
    }
    return $id;
}
echo getIdByUrl($url).'<hr/>';
 
//获取完整文件名
echo basename($url).'<hr/>';
 
//获取没有后缀的文件名
echo basename($url,".html");
 
?>