解决java.sql.Timestamp丢失精度的问题

        Timestamp t1 = Timestamp.valueOf("2019-12-13 15:19:53.2202080");        
        Timestamp t2 = new Timestamp(1576250393220208000L / 1000000L);
        t2.setNanos((int) (1576250393220208000L % 1000000000L));

@Test
public void getCurrentTime(){
	//第一种
	Date date = new Date();
	Timestamp currentTime1 = new Timestamp(date.getTime());
	System.out.println("currentTime1:"+currentTime1);
	//第二种
	Timestamp currentTime2 = new Timestamp(System.currentTimeMillis());
	System.out.println("currentTime2:"+currentTime2);
}

@Test
public void strinGConvertTimestamp(){
	String timeStr = "2016-12-18 11:16:33.706";
	Timestamp ts = Timestamp.valueOf(timeStr);
	System.out.println(ts);
}

@Test
public void timestampConvertString(){
	SimpleDateFORMat sdf = new SimpleDateFormat("yyy-MM-dd HH:mm:ss");
	Timestamp currentTime = new Timestamp(System.currentTimeMillis());
	String timeStr = sdf.format(currentTime);
	System.out.println(timeStr);
}

package com.demo; 
import java.sql.Timestamp;
import java.text.SimpleDateFormat;
import java.util.Date; 
import org.junit.Test; 
public class DemoTimestamp {
	@Test
	public void getCurrentTime(){
		//第一种
		Date date = new Date();
		Timestamp currentTime1 = new Timestamp(date.getTime());
		System.out.println("currentTime1:"+currentTime1);
		//第二种
		Timestamp currentTime2 = new Timestamp(System.currentTimeMillis());
		System.out.println("currentTime2:"+currentTime2);
	}
	@Test
	public void stringConvertTimestamp(){
		String timeStr = "2016-12-18 11:16:33.706";
		Timestamp ts = Timestamp.valueOf(timeStr);
		System.out.println(ts);
	}
	@Test
	public void timestampConvertString(){
		SimpleDateFormat sdf = new SimpleDateFormat("yyy-MM-dd HH:mm:ss");
		Timestamp currentTime = new Timestamp(System.currentTimeMillis());
		String timeStr = sdf.format(currentTime);
		System.out.println(timeStr);
	}
}