C语言版约瑟夫问题算法实现

# include <stdio.h>
# include <malloc.h>
 
typedef struct node
{
	int number;
	struct Node * pNext;
}NODE, *PNODE;
 
PNODE creat_list(int n);
 
int main (void)
{
	int n,m,s;
	printf("约瑟夫环问题：\n");
	printf("设有n（编号为“0 1 2 3 .....n-1 n”）个人围坐一圈,现从第s个人开始报数，数到m的人出列,\n求最后的出列顺序。\n");
	printf("请设置n, s, m ：\n");
	printf("n = ");
	scanf("%d", &n);
	printf("s = ");
	scanf("%d", &s);
	printf("m = ");
	scanf("%d", &m);                    //问题引导提示代码段
 
 
	PNODE pHead = NULL;
	pHead = creat_list(n); 
    pHead->number = 1;                   //创建单链表
 
	PNODE p = pHead;                       //定义头指针
	int i,j,k;                            //定义循环参数
	for(j = 1; j < s; j++)
		{
			p = p->pNext;
		}                                //第一个循环确定第一个报数的人在循环单链表中的位置  
 
	for(i = 1; i <= n; i++)              //外部循环代表遍历到最后一个所需要的循环次数
	{
		for(k = 1; k < m; )              //内部循环代表遍历出列的人
		{
			if(p -> pNext -> number != 0)
			{
				p = p -> pNext;
				k++;
			}
			else
			{
				p = p -> pNext;
			}
		}
		printf("%d  ",p -> number);
		p -> number = 0;
	    do
		{
		    p = p -> pNext;
		}while(p -> number == 0); 
	}
	printf("\n");
	
	return 0;
}
PNODE creat_list(int n)                        //单链表的创建
{
	PNODE pHead = (PNODE)malloc(sizeof(NODE));
    PNODE pTail = pHead;
	int i;
    for(i = 2; i <= n; i++)
	{
		PNODE pNew = (PNODE)malloc(sizeof(NODE));
		pNew->number = i;
		pTail->pNext = pNew;
		pNew->pNext = pHead;
		pTail = pNew;
	}
	return pHead;
}