如何将Python编译成C语言

# encoding=utf-8
# cython: language_level=3
import time
import pyximport

pyximport.install()
import pyth_triples


def main():
    start = time.time()
    result = pyth_triples.count_triples(1000)
    duration = time.time() - start
    print(result, duration * 1000, "ms")


if __name__ == '__main__':
    main()

# encoding=utf-8
# cython: language_level=3
def count_triples(limit):
    result = 0

    for a in range(1, limit + 1):
        for b in range(a + 1, limit + 1):
            for c in range(b + 1, limit + 1):
                if c ** 2 > a ** 2 + b ** 2:
                    break
                if c ** 2 == (a ** 2 + b ** 2):
                    result += 1
    return result

# encoding=utf-8
# cython: language_level=3
def count_triples(limit):
    cdef int result = 0
    cdef int a = 0
    cdef int b = 0
    cdef int c = 0
    for a in range(1, limit + 1):
        for b in range(a + 1, limit + 1):
            for c in range(b + 1, limit + 1):
                if c ** 2 > a ** 2 + b ** 2:
                    break
                if c ** 2 == (a ** 2 + b ** 2):
                    result += 1
    return result

# encoding=utf-8
# cython: language_level=3
from distutils.core import setup

from Cython.Build import cythonize

# set PythonHOME=D:\Anaconda3
# conda activate
# python setup.py build_ext --inplace
setup(
    ext_modules=cythonize("pyth_triples.pyx")
)

set PYTHONHOME=D:\Anaconda3
conda activate
python setup.py build_ext --inplace

public class TriplesTest {
    public static void main(String[] args) {
        long startTime = System.currentTimeMillis();
        System.out.println(count_triples(1000));
        long endTime = System.currentTimeMillis();
        System.out.println("run time:" + (endTime - startTime) + "ms");
    }

    public static int count_triples(int limit) {
        int result = 0;
        for (int a = 1; a <= limit; a++) {
            for (int b = a + 1; b <= limit; b++) {
                for (int c = b + 1; c <= limit; c++) {
                    if (Math.pow(c, 2) > Math.pow(a, 2) + Math.pow(b, 2)) {
                        break;
                    }
                    if (Math.pow(c, 2) == Math.pow(a, 2) + Math.pow(b, 2)) {
                        result += 1;
                    }
                }
            }
        }
        return result;
    }
}