JavaScript中如何在一个循环中等待示例代码详解

const fun = (prop) => {
  return new Promise(resolve => {
    setTimeout(() =>
      resolve(`done ${prop}`), 1000);
  })
}

const Go = async () => {
  const list = [1, 2, 3]
	
  for (const prop of list) {
    console.log(prop)
    console.log(await fun(prop))
  }
  
  console.log('done all')
}

go()

const fun = (prop) => {
  return new Promise(resolve => {
    setTimeout(() =>
      resolve(`done ${prop}`), 1000);
  })
}
const go = async () => {
  const obj = { a: 1, b: 2, c: 3 };

  for (const prop in obj) {
    console.log(prop)
    console.log(await fun(prop))
  }
  
  console.log('done all')
}

go()