C语言中函数返回值不一致问题

#include <stdio.h>
#include <ctype.h>
int *count_e(char *str);
int main(){
	char str[] = {"abc,cba,def"};
	int *a,i;
	a = count_e(str);
	puts("\n");
	for(i=0;i<5;i++){
		printf(" a[%d] = %d ; &a = %p;\n",i,a[i],&a[i]);
	}
	free(a);
	return 0; 
} 

int *count_e(char *str){
	if(str == NULL)
		return NULL;
	int ls[5] = {0};       //关键！！！内存污染问题！ 
	int i,k,t;
	i = k = t = 0;
	while(isspace(str[i]))
		i++;                
	while(str[i]){
		if(isupper(str[i])){
			ls[1]++;k=1;
		}else if(islower(str[i])){
			ls[2]++;k=1;
		}else if(isdigit(str[i])){
			ls[4]++;k=1;
		}else if(isspace(str[i])){
			t = 1;
		}else{
			ls[3]++;t=1;
		} 
		if(k==1 && t ==1){
			ls[0]++;
			k = t = 0;
		}
		i++;
	} 
	for(t=0;t<5;t++)
		printf("ls[%d] = %d ; &ls[i] = %p\n",t,ls[t],&ls[t]);
	if(! isspace(str[--i]))
		ls[0]++;
	return ls;
}

#include <stdio.h>
#include <ctype.h>
int *count_e(char *str);
int main(){
	char str[] = {"abc,cba,def"};
	int *a,i;
	a = count_e(str);
	for(i=0;i<5;i++){
		printf(" a[%d] = %d ; &a = %p;\n",i,a[i],&a[i]);
	}
	free(a);
	return 0; 
} 

int *count_e(char *str){
	if(str == NULL)
		return NULL;
	int *ls = (int *)calloc(5,sizeof(int)); //ls[5] = {0}; ！！！注意不同！！！内存污染问题！** 
	int i,k,t;
	i = k = t = 0;
	while(isspace(str[i]))
		i++;                
	while(str[i]){
		if(isupper(str[i])){
			ls[1]++;k=1;
		}else if(islower(str[i])){
			ls[2]++;k=1;
		}else if(isdigit(str[i])){
			ls[4]++;k=1;
		}else if(isspace(str[i])){
			t = 1;
		}else{
			ls[3]++;t=1;
		} 
		if(k==1 && t ==1){
			ls[0]++;
			k = t = 0;
		}
		i++;
	} 
	for(t=0;t<5;t++)
		printf("ls[%d] = %d ; &ls[i] = %p\n",t,ls[t],&ls[t]);
	if(! isspace(str[--i]))
		ls[0]++;
	return ls;
}