详细解读Java的Lambda表达式

submit.addActionListener(new ActionListener() {
	@Override
	public void actionPerfORMed(ActionEvent e) {
		JOptionPane.showMessageDialog(null, "点击了确定按钮", "确定", JOptionPane.INFORMATION_MESSAGE);
	}
});

submit.addActionListener((e)->{
		JOptionPane.showMessageDialog(null, "点击了确定按钮", "确定", JOptionPane.INFORMATION_MESSAGE);
});

ActionListener listener = e->JOptionPane.showMessageDialog(null, "点击了确定按钮", "确定", JOptionPane.INFORMATION_MESSAGE);

List<Dog> dogs1 = new ArrayList<Dog>();

List<Dog> dogs2 = new ArrayList<>(); 

BinaryOperator b = (x, y)->x*y;
//上面这句代码无法通过编译，下面是报错信息：无法将 * 运算符作用于 java.lang.Object 类型。
The operator * is undefined for the argument type(s) java.lang.Object, java.lang.Object

//添加参数类型，正确的代码。
BinaryOperator<Integer> b = (x, y)->x*y;

ActionListener listener = e->JOptionPane.showMessageDialog(null, "点击了确定按钮", "确定", JOptionPane.INFORMATION_MESSAGE);

import java.text.ParseException;
import java.util.function.BinaryOperator;
import java.util.function.Consumer;
import java.util.function.Function;
import java.util.function.Predicate;
import java.util.function.Supplier;
import java.util.function.UnaryOperator;
import java.util.stream.Stream;

public class Test {
	public static void main(String[] args) throws ParseException {
		//Lambda 表达式中的构造器引用，用于简化代码。
		Creat<Dog> c = Dog::new;
		Dog dog = c.creat("小黑", 15);
		System.out.println(dog.toString());
		
		Predicate<String> predicate = (Words)->{
			return words.length() > 20;
		};
		assert predicate.test("I love you yesterday and today!") : "长度小于20";
		assert !predicate.test("God bless you!") : "长度小于20";
		System.out.println("------------------------");
		
		Consumer<Dog> consumer = System.out::println;
		consumer.accept(dog);
		System.out.println("------------------------");

		Function<Dog, String> function = (dogObj)->{
			return dogObj.getName();
		};
		System.out.println(function.apply(dog));
		System.out.println("------------------------");
		
		Supplier<Dog> supplier = ()->{
			return new Dog("大黄", 4);
		};
		System.out.println(supplier.get());
		
		//一元操作符
		UnaryOperator<Boolean> unaryOperation = (flag)->{
			return !flag;
		};
		System.out.println(unaryOperation.apply(true));
		
		BinaryOperator<Integer> binaryOperator = (x, y)->x*y;
		int result = binaryOperator.apply(999, 9999);
		System.out.println(result);
	}
}

public class Dog {
	private String name;
	private int age;
	
	public Dog(String name, int age) {
		this.name = name;
		this.age = age;
	}

	public String getName() {
		return name;
	}

	public void setName(String name) {
		this.name = name;
	}

	public int getAge() {
		return age;
	}

	public void setAge(int age) {
		this.age = age;
	}

	@Override
	public String toString() {
		return "Dog [name=" + name + ", age=" + age + "]";
	}
}

@FunctionalInterface
public interface Creat<T> {
	public T creat(String name, int age);
}

		List<Dog> dogs = new ArrayList<>();
		dogs.add(new Dog("大黄", 2));
		dogs.add(new Dog("小黑", 3));
		dogs.add(new Dog("小哈",1));
		//将行为像数据一样传递，使用集合的 forEach 方法来遍历集合，
		//参数可以是一个 Lambda 表达式。
		Consumer<? super Dog> con = (e)->{
			System.out.println(e);
		};
		dogs.forEach(con);
		System.out.println("--------------------------\n");
	
		//直接传递 Lambda 表达式，更加简洁
		dogs.forEach(e->System.out.println(e));
		System.out.println("--------------------------\n");

		//使用方法引用，进一步简化（可以看我的另一篇关于方法引用的博客）
		dogs.forEach(System.out::println);
		System.out.println("--------------------------\n");

		//使用 Lambda 对集合进行定制排序，按照年龄排序（从小到大）。
		dogs.sort((e1, e2)->e1.getAge()-e2.getAge());
		dogs.forEach(System.out::println);