es6的set集合怎么增加元素

let set = new Set()
set.add(1);
console.log(set);
set.add(1).add(2).add(1)
console.log(set)
//注：拓展运算符 （...）可以将Set值扩展出来
console.log(...set)
console.log([...set])

let set = new Set()
set.add(1).add(2);
let a = set.delete(1);
console.log(set)
//注：拓展运算符 （...）可以将Set值扩展出来
console.log(...set)
console.log(a)
set.delete(3)
console.log(...set)

let set = new Set()
set.add(1).add(2);
let a = set.has(1);//true
let b = set.has(3);//false
console.log(a,b)

let set = new Set();
set.add(1).add(2);
set.clear();
console.log(set,[...set]);//Set(0){} []

let set = new  Set();
set.add(1).add(2).add(3)
for(let i of set.keys()){   //keys遍历
    console.log(i)
}
for(let i of set.values()){ //values遍历
    console.log(i)
}
set.add('hello').add('world');
for( let i of set.entries() ){ //打印键值对
    console.log(i) 
}

let set = new Set();
set.add('hello').add('world');
set.forEach((key,val)=>{
    console.log(key + '||' + val)
})

let arr = ['小红','小明','小强','小明'];
let set = new Set(arr);
console.log(...set)

let arr = [4,5,6];
let list = [5,6,7];
let setA = new Set(arr);
let setB = new Set(list);
//并集 ：集合A与集合 B的并集A U B
let bj = new Set([...setA,...setB])
console.log(bj)// 返回Set结构 Set(4) {4,5,6,7}
//交集：集合A 与 集合B 的交集 A ∩ B
let jj = new Set([...setA].filter(val => setB.has(val)))//通过 filter拿到符合条件的值
console.log(jj)//Set(2) { 5, 6 }