Android应用中怎么将文件上传到服务器

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1)、新建一个Android项目命名为androidUpload，目录结构如下：

2)、新建FORMFile类，用来封装文件信息

package com.ljq.utils;import java.io.File;import java.io.FileInputStream;import java.io.FileNotFoundException;import java.io.InputStream;public class FormFile {  private byte[] data; private InputStream inStream; private File file;  private String filname;  private String parameterName;  private String contentType = "application/octet-stream";  public FormFile(String filname, byte[] data, String parameterName, String contentType) {  this.data = data;  this.filname = filname;  this.parameterName = parameterName;  if(contentType!=null) this.contentType = contentType; }  public FormFile(String filname, File file, String parameterName, String contentType) {  this.filname = filname;  this.parameterName = parameterName;  this.file = file;  try {   this.inStream = new FileInputStream(file);  } catch (FileNotFoundException e) {   e.printStackTrace();  }  if(contentType!=null) this.contentType = contentType; }  public File getFile() {  return file; } public InputStream getInStream() {  return inStream; } public byte[] getData() {  return data; } public String getFilname() {  return filname; } public void setFilname(String filname) {  this.filname = filname; } public String getParameterName() {  return parameterName; } public void setParameterName(String parameterName) {  this.parameterName = parameterName; } public String getContentType() {  return contentType; } public void setContentType(String contentType) {  this.contentType = contentType; } }