javaweb中ajax请求后台servlet(实例)

废话不多说，直接上代码

public class DZFP_jdbc extends httpservlet{  private static final long serialVersionUID = 1L;  public static Connection conn;   public static ResultSet rs = null ;    public static PreparedStatement ps = null ;  private static String url = "jdbc:oracle:thin:@192.168.100.11:1111:CRM";  private static String name = "name";  private static String pwd = "pwd";  protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {        response.setCharacterEncoding("utf-8");    request.setCharacterEncoding("utf-8");    response.setHeader("content-type", "text/html;charset=UTF-8");    PrintWriter out = response.getWriter();    ***********    out.print("{\"errorno\":[{\"list\":error}]}");  }}$.ajax({   type: "post",   url: "DZFP_jdbc",   dataType: "text",     data : {      taxcode : taxcode,      mobilenum : mobilenum  },  timeout : 50000,    success: function (data) {   var JSONobjs = eval("(" + data + ")");  var list = jsonobjs.errorno[0].list;    },   error: function() {      alert("网络异常，请稍后重试");  } });<servlet>  <servlet-name>DZFP_jdbc</servlet-name>  <servlet-class>  weishijiestudio.hangxinwx.servlet.DZFP_jdbc  </servlet-class></servlet><servlet-mapping>  <servlet-name>DZFP_jdbc</servlet-name>  <url-pattern>/DZFP_jdbc</url-pattern></servlet-mapping>