Android字符串和十六进制相互转化出现的中文乱码问题

废话不读说了，直接给大家贴代码了，代码附有注释，可以说明一切，本文写的不好，还请见谅。

import java.io.ByteArrayOutputStream;

public class StringToSixthUtils {
private static String hexString = "0123456789abcdef";

public static String encode(String str) {
//根据默认编码获取字节数组
byte[] bytes = str.getBytes();
StringBuilder sb = new StringBuilder(bytes.length * 2);
//将字节数组中每个字节拆解成2位16进制整数
for (int i = 0; i < bytes.length; i++) {
sb.append(hexString.charAt((bytes[i] & 0xf0) >> 4));
sb.append(hexString.charAt((bytes[i] & 0x0f)));
}
return sb.toString();
}

public static String decode(String bytes) {
ByteArrayOutputStream baos = new ByteArrayOutputStream(bytes.length() / 2);
//将每2位16进制整数组装成一个字节
for (int i = 0; i < bytes.length(); i += 2)
baos.write((hexString.indexOf(bytes.charAt(i)) << 4 | hexString.indexOf(bytes.charAt(i + 1))));
return new String(baos.toByteArray());
}
}

下面给大家分享一段代码关于16进制字符串和字节数组互相转换

package com.wpn.net.util; 
public class NumberChange { 
 
public static byte[] hexStringToByte(String hex) { 
int len = (hex.length() / 2); 
byte[] result = new byte[len]; 
char[] achar = hex.toCharArray(); 
for (int i = 0; i < len; i++) { 
int pos = i * 2; 
result[i] = (byte) (toByte(achar[pos]) << 4 | toByte(achar[pos + 1])); 
} 
return result; 
} 
private static byte toByte(char c) { 
byte b = (byte) "0123456789ABCDEF".indexOf(c); 
return b; 
} 
 
public static final String bytesToHexString(byte[] bArray) { 
StringBuffer sb = new StringBuffer(bArray.length); 
String sTemp; 
for (int i = 0; i < bArray.length; i++) { 
sTemp = Integer.toHexString(0xFF & bArray[i]); 
if (sTemp.length() < 2) 
sb.append(0); 
sb.append(sTemp.toUpperCase()); 
} 
return sb.toString(); 
} 
 
public static String bcd2Str(byte[] bytes) { 
StringBuffer temp = new StringBuffer(bytes.length * 2); 
for (int i = 0; i < bytes.length; i++) { 
temp.append((byte) ((bytes[i] & 0xf0) >>> 4)); 
temp.append((byte) (bytes[i] & 0x0f)); 
} 
return temp.toString().substring(0, 1).equalsIgnoreCase("0") ? temp.toString().substring(1) : temp.toString(); 
} 
 
public static byte[] str2Bcd(String asc) { 
int len = asc.length(); 
int mod = len % 2; 
if (mod != 0) { 
asc = "0" + asc; 
len = asc.length(); 
} 
byte abt[] = new byte[len]; 
if (len >= 2) { 
len = len / 2; 
} 
byte bbt[] = new byte[len]; 
abt = asc.getBytes(); 
int j, k; 
for (int p = 0; p < asc.length() / 2; p++) { 
if ((abt[2 * p] >= '0') && (abt[2 * p] <= '9')) { 
j = abt[2 * p] - '0'; 
} else if ((abt[2 * p] >= 'a') && (abt[2 * p] <= 'z')) { 
j = abt[2 * p] - 'a' + 0x0a; 
} else { 
j = abt[2 * p] - 'A' + 0x0a; 
} 
if ((abt[2 * p + 1] >= '0') && (abt[2 * p + 1] <= '9')) { 
k = abt[2 * p + 1] - '0'; 
} else if ((abt[2 * p + 1] >= 'a') && (abt[2 * p + 1] <= 'z')) { 
k = abt[2 * p + 1] - 'a' + 0x0a; 
} else { 
k = abt[2 * p + 1] - 'A' + 0x0a; 
} 
int a = (j << 4) + k; 
byte b = (byte) a; 
bbt[p] = b; 
} 
return bbt; 
} 
public static void main(String[] arg) { 
 
String[] str = {"C4", "E3", "BA", "C3"}; 
// String[] str = {"7E","02","04","00","07","10","00","00","00","00","13","08","4F","01","0B","0B","15","10","14","13","44","7E"}; 
byte[] b = new byte[str.length]; 
for(int i=0;i<str.length;i++){ 
b[i] = hexStringToByte(str[i])[0]; 
} 
System.out.println(new String(b)); 
String strC ="你好"; 
String bth=bytesToHexString(strC.getBytes()); 
System.out.println(bth); 
System.out.println(Short.MAX_VALUE); 
System.out.println(Integer.toBinaryString(280)); 
} 
}

以上所述是本文给大家分享的Android字符串和十六进制相互转化出现的中文乱码问题的相关内容，希望对大家有所帮助。

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