Python实现字符串反转的6种方法

1.使用字符串切片

>>> s = "python">>> s[::-1]'nohtyp'>>>

2.使用列表的reverse方法

>>> s = "Python">>> lst = list(s)>>> lst.reverse()>>> "".join(lst)'nohtyp'>>>

手写 reverse

>>> def reverseString(s:str) -> str:    lst = list(s)    i, j = 0, len(s)-1    while i < j:        lst[i], lst[j] = lst[j], lst[i]        i , j = i + 1, j - 1    return "".join(lst) >>> s = 'python'>>> reverseString(s)'nohtyp'>>>

3.使用reduce

>>> from functools import reduce  # python3 中不可以直接调用reduce>>> s = "python">>> reduce(lambda x, y: y+x, s)'nohtyp'>>>

reduce 函数帮助：

>>> help(reduce)Help on built-in function reduce in module _functools: reduce(...)    reduce(function, sequence[, initial]) -> value         Apply a function of two arguments cumulatively to the items of a sequence,    from left to right, so as to reduce the sequence to a single value.    For example, reduce(lambda x, y: x+y, [1, 2, 3, 4, 5]) calculates    ((((1+2)+3)+4)+5).  If initial is present, it is placed before the items    of the sequence in the calculation, and serves as a default when the    sequence is empty. >>>

4.使用递归函数

>>> def reverse(s):    if s == "":        return s    else:        return reverse(s[1:]) + s[0]      >>> reverse('python')'nohtyp'>>>

python中默认的最大递归数：

>>> import sys>>> sys.getrecursionlimit()1000>>>

5.使用栈

>>> def rev(s):    lst = list(s) # 转换成list    ret = ""    while len(lst):        ret += lst.pop() # 每次弹出最后的元素    return ret#Python小白学习交流群：711312441 >>> s = 'python'>>> rev(s)'nohtyp'>>>

6.for循环

>>> def rever(s):    ret = ""    for i in range(len(s)-1, 0, -1):        ret += s[i]    return ret >>> s = "python">>> rev(s)'nohtyp'>>> 

来源地址：https://blog.csdn.net/Python_222/article/details/130108777