Go语言中如何处理并发文件的文件系统路径处理和文件名编码问题？

package main

import (
    "fmt"
    "path/filepath"
)

func main() {
    dir := "/home/user"
    filename := "test.txt"
    path := filepath.Join(dir, filename)
    fmt.Println(path) // 输出：/home/user/test.txt
}

package main

import (
    "fmt"
    "path/filepath"
)

func main() {
    path := "/home/user/test.txt"
    dir := filepath.Dir(path)
    fmt.Println(dir) // 输出：/home/user
}

package main

import (
    "fmt"
    "path/filepath"
)

func main() {
    path := "/home/user/test.txt"
    filename := filepath.Base(path)
    fmt.Println(filename) // 输出：test.txt
}

package main

import (
    "fmt"
    "os"
)

func main() {
    filePath := "C:/测试文件.txt"
    info, err := os.Stat(filePath)
    if err != nil {
        fmt.Println("获取文件信息失败：", err)
        return
    }

    fmt.Println("文件名：", info.Name())
}

package main

import (
    "fmt"
    "path/filepath"
)

func main() {
    pattern := "/home/user/测试文件*"
    matches, err := filepath.Glob(pattern)
    if err != nil {
        fmt.Println("获取匹配文件列表失败：", err)
        return
    }

    fmt.Println("匹配的文件列表：")
    for _, match := range matches {
        fmt.Println(match)
    }
}

package main

import (
    "fmt"
    "os"
    "sync"
)

var (
    file    *os.File
    mutex   sync.Mutex
)

func main() {
    var err error
    file, err = os.OpenFile("test.txt", os.O_RDWR|os.O_CREATE|os.O_APPEND, 0644)
    if err != nil {
        fmt.Println("打开文件失败：", err)
        return
    }
    defer file.Close()

    writeToFile("Hello, World!")
    readFromFile()
}

func writeToFile(content string) {
    mutex.Lock()
    defer mutex.Unlock()

    _, err := file.WriteString(content)
    if err != nil {
        fmt.Println("写入文件失败：", err)
        return
    }
}

func readFromFile() {
    mutex.Lock()
    defer mutex.Unlock()

    data := make([]byte, 1024)
    n, err := file.Read(data)
    if err != nil {
        fmt.Println("读取文件失败：", err)
        return
    }

    fmt.Println("文件内容：", string(data[:n]))
}