Python双端队列deque的实现

import collections

c = collections.deque('abcdefg')
print("输出双端队列：", c)
print("双端队列的长度：", len(c))
print("前端值：", c[0])
print("末端值：", c[-1])

import collections

c = collections.deque()
#不使用构造函数初始化
c.extend("abcdefg")
#右端（末端）添加
c.append('h')
print(c)
#左端添加（前端）添加
c.extendleft('i')
print(c)
#末尾删除
c.pop()
print(c)
#前端删除
c.popleft()
print(c)
#随便删除
c.remove('c')
print(c)

import collections
import threading
import time

def getItem(lor, method):
    while True:
        try:
            next = method()
        except IndexError:
            break
        else:
            print("{0}:{1}".fORMat(lor, next))
            time.sleep(0.1)
    print('{0}:None'.format(lor))
    return

c = collections.deque("abcdefg")
t1 = threading.Thread(target=getItem, args=('Left', c.popleft))
t2 = threading.Thread(target=getItem, args=('Right', c.popleft))
t1.start()
t2.start()
t1.join()
t2.join()

import collections

a = collections.deque("abcdefg")
b = collections.deque("abcdefg")
c = collections.deque("abcdefg")
print(a)
b.rotate(2)
print(b)
c.rotate(-2)
print(c)

import collections
import random

c1 = collections.deque(maxlen=5)
c2 = collections.deque(maxlen=3)

for i in range(8):
    r = random.randint(1, 100)
    print(r)
    c1.append(r)
    c2.append(r)
print(c1)
print(c2)