C语言实现BF算法案例详解

#include <stdio.h>
#include <string.h>
 
int BF(const char *s, const char* sub, int pos)//O(n*m)
{
	int i = pos;
	int j = 0;
	int lens = strlen(s);
	int lensub = strlen(sub);
	while (i<lens && j<lensub)
	{
		if (s[i] == sub[j])
		{
			i++;
			j++;
		}
		else
		{
			i = i - j + 1;//i退回到当前匹配失败初始的下一个
			j = 0;//j回退到0
		}
	}
	if (j >= lensub)
	{
		return i - j;
	}
	else
	{
		return -1;
	}
}
 
int main()
{
	char *s = "ababcabcdfabcde";
	char *sub = "abcd";
	printf("%d\n", BF(s, sub, 0));
	return 0;
}