JAVA如何删除字符串固定下标字串

本篇内容主要讲解“JAVA如何删除字符串固定下标字串”，感兴趣的朋友不妨来看看。本文介绍的方法操作简单快捷，实用性强。下面就让小编来带大家学习“JAVA如何删除字符串固定下标字串”吧!

需要修改的报文

当你拿到的报文是这样的

{    "input": {        "sdfsn": "23u4209350-2",        "fsfs": "128412094",        "sgsgsg": "15821059",        "inssgsuplc_admdfdfdvs": "125125332",        "dgh": "125215312",        "dfgdfg": "215215",        "sdhdsh": "",        "sdfsn": "",        "shdfshdshdsh": "shsdh",        "sdhdsh": "shsh.0",        "shsdhsd": "1",        "shsdh": "1607",        "input": {            "data": {                "dhfsdhsd": "235325",                "shsdhsdh": "03",                "dgd": "BE0445360",                "dfhfdh": "11",                "dshshsd": 76.56,                "ghjrfgj": "01",                "grjf": "234623626",                "hjfd": "236436",                "djfdfgjdfj": "45634",                "exp_Content": "{"gdsg":"01","gjfj":"658568","fjfj":"5675467","ghfjfgkj":"68568","vmgfvj":"658568","gfhjgfyk":"0","fghkfghkg":"5474567"}",                "dfjgdfj": "",                "dfjdfjgdfj": "56745745",                "dfgjdfgjh": 45756758,                "jdfgjhfdgj": 0,            }        }    },    "output": {        "output": {            "r757": {                "dhfsdhsd": "235325",                "shsdhsdh": "03",                "dgd": "BE0445360",                "dfhfdh": "11",                "dshshsd": 76.56,                "ghjrfgj": "01",                "grjf": "234623626",                "hjfd": "236436",                "djfdfgjdfj": "45634",                "exp_content": "",                "dfjgdfj": "",                "dfjdfjgdfj": "56745745",                "dfgjdfgjh": 45756758,                "jdfgjhfdgj": 0,            },            "sdfgsdfg": [                {                    "sgasgag": "4673476",                    "agasgdas": 5675467,                    "asgasgasg": "",                    "asdgasgas": 4567456754,                    "dhsdsxchsdh": 54675467,                    "sdfhsdhsdh": "5674756457"                }            ]        },        "erherth": 0,    }}

这一看就知道上边的报文在postman里边肯定会报错，因为exp_Content，因此他又没有用到，所以你想把他删掉。其实也没那么难删

也就是用到了流转字符串。字符串固定字符查找，然后进行字符串转字符流，删掉字符流中固定字符，之后再转回来。因为字符串已经是final了所以很多用法都是使用字符串转字符流实现的

实现代码如下

    private JSONObject resolveApplicationjson(httpservletRequest request) {        InputStream is = null;        String json = null;        try {            is = request.getInputStream();            json = IOUtils.toString(is, "UTF-8");            json=json.replaceAll("\\r|\n|\t","");            int index=  json.indexOf("exp_Content");            int indexfirst=json.indexOf("{", index);            int indexlast=json.indexOf("}",index);            if (index!=-1 && indexlast !=-1 &&indexfirst !=-1) {              StringBuffer stringBuffer = new StringBuffer(json);                  stringBuffer.delete(indexfirst,indexlast+1);                  json=stringBuffer.toString();}                       } catch (IOException e) {            throw new RuntimeException("CANNOT get reader from request!", e);        } finally {            if (is != null) {                try {                    is.close();                } catch (IOException e) {                    e.printStackTrace();                }            }        }        try {            return new JSONObject(json);        } catch (JSONException e) {            throw new RuntimeException("CANOT CONVET JSON:[" + json + "] to JSONObject!", e);        }    }

多存在多个不符合规定的数据然后你要删掉怎么操作呢？

当你拿到的报文是这样的。

{    "input": {        "sdfsn": "23u4209350-2",        "fsfs": "128412094",        "sgsgsg": "15821059",        "inssgsuplc_admdfdfdvs": "125125332",        "dgh": "125215312",        "dfgdfg": "215215",        "sdhdsh": "",        "sdfsn": "",        "shdfshdshdsh": "shsdh",        "sdhdsh": "shsh.0",        "shsdhsd": "1",        "shsdh": "1607",        "input": {            "data": {                "dhfsdhsd": "235325",                "shsdhsdh": "03",                "dgd": "BE0445360",                "dfhfdh": "11",                "dshshsd": 76.56,                "ghjrfgj": "01",                "grjf": "234623626",                "hjfd": "236436",                "djfdfgjdfj": "45634",                "exp_Content": "{"gdsg":"01","gjfj":"658568","fjfj":"5675467","ghfjfgkj":"68568","vmgfvj":"658568","gfhjgfyk":"0","fghkfghkg":"5474567"}",                "dfjgdfj": "",                "dfjdfjgdfj": "56745745",                "dfgjdfgjh": 45756758,                "jdfgjhfdgj": 0,            }        }    },    "output": {        "output": {            "r757": {                "dhfsdhsd": "235325",                "shsdhsdh": "03",                "dgd": "BE0445360",                "exp_Content": "{"gdsg":"01","gjfj":"658568","fjfj":"5675467","ghfjfgkj":"68568","vmgfvj":"658568","gfhjgfyk":"0","fghkfghkg":"5474567"}",                "dfhfdh": "11",                "dshshsd": 76.56,                "ghjrfgj": "01",                "grjf": "234623626",                "hjfd": "236436",                "djfdfgjdfj": "45634",                "exp_content": "{"gdsg":"01","gjfj":"658568","fjfj":"5675467","ghfjfgkj":"68568","vmgfvj":"658568","gfhjgfyk":"0","fghkfghkg":"5474567"}",                "dfjgdfj": "",                "dfjdfjgdfj": "56745745",                "dfgjdfgjh": 45756758,                "jdfgjhfdgj": 0,            },            "sdfgsdfg": [                {                    "sgasgag": "4673476",                    "agasgdas": 5675467,                    "asgasgasg": "",                    "asdgasgas": 4567456754,                    "dhsdsxchsdh": 54675467,                    "sdfhsdhsdh": "5674756457"                }            ]        },        "erherth": 0,    }}

解决方式如下：根据需要写出正则表达式，再使用正则看看有几个这样的不需要的符号，然后循环遍历几次，之后找到这部分，最后删除掉。

实现代码如下

# 全局变量private static String REGEX = "exp_[c,C]ontent";# 方式方法Pattern p = Pattern.compile(REGEX);        // 获取 matcher 对象        Matcher m = p.matcher(JSON);        List<Integer> list = new ArrayList();        while(m.find()){            list.add(m.start());        }        int index=0;        int indexfirst=0;        int indexlast=0;        for (int j = 0; j < list.size(); j++) {             index=JSON.indexOf("exp_",indexlast);             indexfirst=JSON.indexOf("{", index);             indexlast=JSON.indexOf("}",index);            StringBuffer stringBuffer =null;            if (indexlast !=-1 &&indexfirst !=-1) {                stringBuffer = new StringBuffer(JSON);                stringBuffer.delete(indexfirst,indexlast+1);            }            JSON=stringBuffer.toString();        }

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