Python 实现反转整数的案例(很容易懂的那种)

tra = 0
while x != 0:
　　n2 = x%10
　　x = x //10
　　tra = tra*10 + n2

class Solution(object):
 def reverse(self, x):
 base = 1
 for i in range(31):
 base = base * 2
 two_Max = base - 1
 two_Min = -base
 tra = 0
 if x < 0:
 x = abs(x)
 while x != 0:
 n2 = x % 10
 if tra > abs(two_Min) // 10 or (tra == abs(two_Min) // 10 and n2 < -8):
  return 0
 x = x // 10
 tra = tra * 10 + n2
 return -tra
 else:
 while x != 0:
 n2 = x % 10
 if tra > two_Max//10 or (tra == two_Max and n2 > 7 ):
  return 0
 x = x // 10
 tra = tra * 10 + n2
 return tra

x, y = 1, 2 
print(x, y) 
x, y = y, x 
print(x, y)

sentence_list = ["my", "name", "is", "George"] 
sentence_string = " ".join(sentence_list) 
print(sentence_string)

sentence_string = "my name is George" 
sentence_string.split() 
print(sentence_string)

[0]*1000 
# List of 1000 
zeros [8.2]*1000 
# List of 1000 8.2's

x = {'a': 1, 'b': 2} 
y = {'b': 3, 'c': 4} 
z = {**x, **y}

name = "George" name[::-1] 

def get_a_string(): 
a = "George" 
b = "is" 
c = "cool" return a, b, c 
sentence = get_a_string() (a, b, c) = sentence

a = [1, 2, 3] 
b = [num*2 for num in a] # Create a new list by multiplying each element in a by 2

m = {'a': 1, 'b': 2, 'c': 3, 'd': 4} for key, value in m.items(): print('{0}: {1}'.fORMat(key, value))

m = ['a', 'b', 'c', 'd'] for index, value in enumerate(m): print('{0}: {1}'.format(index, value))

a_list = list() 
a_dict = dict() 
a_map = map() 
a_set = set()

name = " George " name_2 = "George///" name.strip() # prints "George" name_2.strip("/") # prints "George"

test = [1, 2, 3, 4, 2, 2, 3, 1, 4, 4, 4] print(max(set(test), key = test.count))

import sys x = 1 print(sys.getsizeof(x))

from xml.etree.ElementTree import Element def dict_to_xml(tag, d): ''' Turn a simple dict of key/value pairs into XML ''' elem = Element(tag) for key, val in d.items(): child = Element(key) child.text = str(val) elem.append(child) return elem